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MHT CET 2026 (11 Apr, Shift 1) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from MHT CET 2026 (11 Apr, Shift 1)

Q3MHT CET 2026 · 11 APR · SHIFT 1Easy

Rotational Kinetic Energy, Work & Power

A flywheel rotating about a fixed axis has a kinetic energy of $500$ joule, if its angular frequency is $5$ Hz, then calculate the moment of inertia of the wheel about the axis of rotation. ( $\pi^2 = 10$ )

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Answer: (b)

$\omega = 2\pi n = 10\pi$ rad/s, so $\omega^2 = 100\pi^2 = 1000$
$K = \frac{1}{2}I\omega^2 \Rightarrow I = \frac{2K}{\omega^2} = \frac{1000}{1000}$
So the answer is (b) $1$ kg m $^2$ .

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