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JEE Main 2023 (29 Jan, Shift 2) · Inertia, First & Second Laws

Inertia, First & Second Laws question from JEE Main 2023 (29 Jan, Shift 2)

Q15JEE Main 2023 · 29 JAN · SHIFT 2Medium

Inertia, First & Second Laws

A force acts for 20 s on a body of mass 20 kg, starting from rest, after which the force ceases and then body describes 50 m in the next 10 s. The value of force will be:

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Answer: (c)

  1. After the force stops, speed is constant: v=5010=5 m/sv = \frac{50}{10} = 5\text{ m/s}.
  2. This speed was gained in 20 s from rest: a=520=0.25 m/s2a = \frac{5}{20} = 0.25\text{ m/s}^2
  3. F=ma=20×0.25=5 NF = ma = 20 \times 0.25 = 5\text{ N}. So the answer is (c) 5 N.
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