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JEE Main 2023 (11 Apr, Shift 1) · Work by a Variable Force

Work by a Variable Force question from JEE Main 2023 (11 Apr, Shift 1)

Q5JEE Main 2023 · 11 APR · SHIFT 1Easy

Work by a Variable Force

A force $\vec{F} = (2 + 3x)\hat{i}$ acts on a particle in the $x$ direction where F is in newton and $x$ is in meter. The work done by this force during a displacement from $x = 0$ to $x = 4\text{ m}$ , is __________ J.

Numerical answer type. Work it out, then open the answer.

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Answer: 32

$W = \int_0^4 (2 + 3x)\,dx = \left[2x + \frac{3x^2}{2}\right]_0^4$
$W = 8 + 24 = 32$ J
Work done $= 32$ J.

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