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NEET 2019 · Work by a Variable Force

Work by a Variable Force question from NEET 2019

Q16NEET 2019Easy

Work by a Variable Force

A force F = 20 + 10y acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is:

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Answer: (b)

$W = \int_0^1 (20 + 10y)\,dy = \left[20y + 5y^2\right]_0^1$
$W = 20 + 5 = 25$ J
So the answer is (b) 25 J.

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