A force F = 2i + bj + k is applied on a particle and it undergoes a displacement i - 2j - k. What will be the value of b, if work done on the particle is zero. (a) 1/3 (b) 1/2 (c) 0 (d) 2

Answer: (b). Zero work means F = 0. 2(1) + b(-2) + 1(-1) = 0 ⇒ 1 - 2b = 0 So the answer is (b) b = 1/2.

A force F = 2i + bj + k is applied on a particle and it undergoes a… | JEE Main 2025 (22 Jan, Shift 2)

Q5JEE Main 2025 · 22 JAN · SHIFT 2Easy

Work by a Constant Force

A force $\vec{F} = 2\hat{i} + b\hat{j} + \hat{k}$ is applied on a particle and it undergoes a displacement $\hat{i} - 2\hat{j} - \hat{k}$ . What will be the value of $b$ , if work done on the particle is zero.

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Answer: (b)

Zero work means $\vec{F}\cdot\vec{s} = 0$ .
$2(1) + b(-2) + 1(-1) = 0 \Rightarrow 1 - 2b = 0$
So the answer is (b) $b = \frac{1}{2}$ .

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