Rolling Motion question from JEE Main 2025 (3 Apr, Shift 1)

Answer: (b)

1. Force at top of a rolling body: $a = \dfrac{2F}{(1+k)m}$ (from $F + f = ma$ and $(F - f)R = I\alpha$).
2. Solid sphere $k = \frac{2}{5}$: $a = \dfrac{2 \times 49}{1.4 \times 20} = \dfrac{98}{28}$.
3. $a = 3.5\ \text{m/s}^2$, so the answer is (b).