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JEE Main 2023 (10 Apr, Shift 2) · Torque, Couple & Equilibrium of Rigid Bodies

Torque, Couple & Equilibrium of Rigid Bodies question from JEE Main 2023 (10 Apr, Shift 2)

Q16JEE Main 2023 · 10 APR · SHIFT 2Medium

Torque, Couple & Equilibrium of Rigid Bodies

A force of −Pk^-P\hat{k} acts on the origin of the coordinate system. The torque about the point (2,−3)(2, -3) is P(ai^+bj^)P(a\hat{i} + b\hat{j}). The ratio of ab\frac{a}{b} is x2\frac{x}{2}. The value of xx is ___________.

Numerical answer type. Work it out, then open the answer.

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Answer: 3

  1. Force acts at origin, so r⃗=O−(2,−3,0)=−2i^+3j^\vec{r} = O - (2,-3,0) = -2\hat{i}+3\hat{j}.
  2. τ⃗=(−2i^+3j^)×(−Pk^)=2P(i^×k^)−3P(j^×k^)=−2Pj^−3Pi^\vec{\tau} = (-2\hat{i}+3\hat{j})\times(-P\hat{k}) = 2P(\hat{i}\times\hat{k}) - 3P(\hat{j}\times\hat{k}) = -2P\hat{j} - 3P\hat{i}
  3. a=−3a = -3, b=−2b = -2, so ab=32=x2\frac{a}{b} = \frac{3}{2} = \frac{x}{2}
  4. x = 3
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