A force on an object of mass 100 g is (10i + 5j) N. The position of that object at t = 2 s is (ai + bj) m after starting from rest. The value of a/b will be ___________. Numerical answer type. Work it out, then open the answer.

Answer: 2. From rest, r = 1/2F/mt², so each coordinate is proportional to the force component. a/b = (Fx)/(Fy) = 10/5 = 2 So a/b = 2.

A force on an object of mass 100 g is (10i + 5j) N. The position of… | JEE Main 2022 (25 Jun, Shift 1)

Q18JEE Main 2022 · 25 JUN · SHIFT 1Medium

Inertia, First & Second Laws

A force on an object of mass 100 g is $\left(10\hat{i} + 5\hat{j}\right)$ N. The position of that object at t = 2 s is $\left(a\hat{i} + b\hat{j}\right)$ m after starting from rest. The value of $\frac{a}{b}$ will be ___________.

Numerical answer type. Work it out, then open the answer.

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Answer: 2

From rest, $\vec{r} = \frac{1}{2}\frac{\vec{F}}{m}t^2$ , so each coordinate is proportional to the force component.
$\frac{a}{b} = \frac{F_x}{F_y} = \frac{10}{5} = 2$
So $\frac{a}{b} = 2$ .

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