A force vector applied on a mass is represented as F = 6i - 8j + 10k and accelerates with 1 m/s². What will be the mass of the body? (a) 10 kg (b) 20 kg (c) 10√(2) kg (d) 2√(10) kg

Answer: (c). |F| = √(6² + (-8)² + 10²) = √(200) = 10√(2) N m = F/a = (10√(2))/(1) = 10√(2) kg So the answer is (c) 10√(2) kg.

A force vector applied on a mass is represented as F = 6i - 8j + 10k… | NEET 1996 (AIPMT)

Q43NEET 1996 · AIPMTEasy

Inertia, First & Second Laws

A force vector applied on a mass is represented as $\vec{F} = 6\hat{i} - 8\hat{j} + 10\hat{k}$ and accelerates with $1\text{ m/s}^2$ . What will be the mass of the body?

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Answer: (c)

$|\vec{F}| = \sqrt{6^2 + (-8)^2 + 10^2} = \sqrt{200} = 10\sqrt{2}\text{ N}$
$m = \frac{F}{a} = \frac{10\sqrt{2}}{1} = 10\sqrt{2}\text{ kg}$
So the answer is (c) $10\sqrt{2}\text{ kg}$ .

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