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JEE Main 2005 (AIEEE) · Energy Stored & Force between Plates

Energy Stored & Force between Plates question from JEE Main 2005 (AIEEE)

Q37JEE Main 2005 · AIEEEMedium

Energy Stored & Force between Plates

A fully charged capacitor has a capacitance ′C′'C'. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity ′s′'s' and mass ′m′.'m'. If the temperature of the block is raised by ′ΔT′,'\Delta T', the potential difference ′v′'v' across the capacitor is

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Answer: (c)

  1. Stored energy becomes heat in the block: 12Cv2=msΔT\frac{1}{2}Cv^2 = ms\Delta T.
  2. v2=2msΔTCv^2 = \frac{2ms\Delta T}{C}
  3. So the answer is (c) 2msΔTC\sqrt{\frac{2ms\Delta T}{C}}.
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