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MHT CET 2026 (11 Apr, Shift 1) · Moving Coil Galvanometer, Ammeter & Voltmeter

Moving Coil Galvanometer, Ammeter & Voltmeter question from MHT CET 2026 (11 Apr, Shift 1)

Q10MHT CET 2026 · 11 APR · SHIFT 1Medium

Moving Coil Galvanometer, Ammeter & Voltmeter

A galvanometer has a current range of 1010 mA and a voltage range of 0.750.75 V. To convert this galvanometer into an ammeter of range 1010 A, what is the shunt resistance?

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Answer: (d)

  1. Galvanometer resistance G=VgIg=0.750.01=75 ΩG = \frac{V_g}{I_g} = \frac{0.75}{0.01} = 75\ \Omega.
  2. Shunt S=IgGI−Ig=0.01×7510−0.01=0.759.99S = \frac{I_g G}{I - I_g} = \frac{0.01 \times 75}{10 - 0.01} = \frac{0.75}{9.99}
  3. S=75999 ΩS = \frac{75}{999}\ \Omega
  4. So the answer is (d) 75999 Ω\frac{75}{999}\ \Omega.
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