A galvanometer has resistance ' G ' Ω and ' Ig ' is current flowing… | MHT CET 2021 (20 Sep, Shift 2)

Q129MHT CET 2021 · 20 SEP · SHIFT 2Medium

Kirchhoff's Laws & Measuring Instruments

A galvanometer has resistance ' $G$ ' $\Omega$ and ' $I_g$ ' is current flowing through it which produces full scale deflection. ' $S_1$ ' is the value of shunt which converts it into an ammeter of range 0 to ' $3I$ ' and ' $S_2$ ' is the shunt value which converts it into an ammeter of range 0 to ' $4I$ ', the ratio $S_2 : S_1$ is

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Answer: (b)

Shunt: $S = \dfrac{I_g G}{I_{max} - I_g}$
$S_1 = \dfrac{I_g G}{3I - I_g}$ , $S_2 = \dfrac{I_g G}{4I - I_g}$
$\dfrac{S_2}{S_1} = \dfrac{3I - I_g}{4I - I_g}$ . So the answer is (b).

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Kirchhoff's Laws & Measuring Instruments question from MHT CET 2021 (20 Sep, Shift 2)

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