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MHT CET 2019 (2 May, Shift 1) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from MHT CET 2019 (2 May, Shift 1)

Q150MHT CET 2019 · 2 MAY · SHIFT 1Easy

Kirchhoff's Laws & Measuring Instruments

A galvanometer has resistance of 100 Ω100\ \Omega and a current of 10 mA produces full scale deflection in it. The resistance to be connected in series, to get a voltmeter of range 50 volt is

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Answer: (d)

  1. Series resistance R=VIg−GR = \frac{V}{I_g} - G.
  2. R=5010×10−3−100=5000−100=4900 ΩR = \frac{50}{10 \times 10^{-3}} - 100 = 5000 - 100 = 4900\ \Omega
  3. So the answer is (d) 4900 Ω4900\ \Omega.
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