Physics Circle home Student Login

Home›Chapters›Current Electricity PYQs›Kirchhoff's Laws & Measuring Instruments›Question 137

JEE Main 2020 (8 Jan, Shift 2) · Kirchhoff's Laws & Measuring Instruments

Kirchhoff's Laws & Measuring Instruments question from JEE Main 2020 (8 Jan, Shift 2)

Q137JEE Main 2020 · 8 JAN · SHIFT 2Easy

Kirchhoff's Laws & Measuring Instruments

A galvanometer having a coil resistance 100 Ω\Omega gives a full scale deflection when a current of 1 mA is passed through it. What is the value of the resistance which can convert this galvanometer into a voltmeter giving full scale deflection for a potential difference of 10 V?

Show answer and solution

Answer: (c)

  1. Series resistance R=VIg−GR = \frac{V}{I_g} - G.
  2. R=1010−3−100=10000−100=9900 Ω=9.9 kΩR = \frac{10}{10^{-3}} - 100 = 10000 - 100 = 9900\ \Omega = 9.9\text{ k}\Omega
  3. So the answer is (c) 9.9 kΩ\Omega.
Report a mistake

More questions on Kirchhoff's Laws & Measuring Instruments