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NEET 2004 (AIPMT) · Moving Coil Galvanometer, Ammeter & Voltmeter

Moving Coil Galvanometer, Ammeter & Voltmeter question from NEET 2004 (AIPMT)

Q31NEET 2004 · AIPMTMedium

Moving Coil Galvanometer, Ammeter & Voltmeter

A galvanometer of 50 ohm resistance has 25 divisions. A current of 4 ×\times 10−-4 ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of

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Answer: (d)

  1. Full-scale current Ig=25×4×10−4=10−2I_g = 25 \times 4 \times 10^{-4} = 10^{-2} A.
  2. Voltmeter needs a series resistance R=VIg−G=2510−2−50R = \frac{V}{I_g} - G = \frac{25}{10^{-2}} - 50
  3. R=2500−50=2450 ΩR = 2500 - 50 = 2450\ \Omega in series
  4. So the answer is (d).
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