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JEE Main 2026 (21 Jan, Shift 1) · Calorimetry, Latent Heat & Mechanical Equivalent of Heat

Calorimetry, Latent Heat & Mechanical Equivalent of Heat question from JEE Main 2026 (21 Jan, Shift 1)

Q3JEE Main 2026 · 21 JAN · SHIFT 1Medium

Calorimetry, Latent Heat & Mechanical Equivalent of Heat

A gas based geyser heats water flowing at the rate of 5.0 litres per minute from 27∘C27^{\circ}\text{C} to 87∘C87^{\circ}\text{C}. The rate of consumption of the gas is ‾ g/s\underline{\hspace{3em}}\text{ g/s}.

(Take heat of combustion of gas =5.0×104 J/g= 5.0 \times 10^{4}\text{ J/g}, specific heat capacity of water =4200 J/kg⋅∘C= 4200\text{ J/kg}\cdot{}^{\circ}\text{C})

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Answer: (d)

  1. Mass flow =5 kg/min=112 kg/s= 5\text{ kg/min} = \tfrac{1}{12}\text{ kg/s}.
  2. Heat per second =112×4200×60=21000 J/s= \tfrac{1}{12} \times 4200 \times 60 = 21000\text{ J/s}
  3. Gas rate =210005×104=0.42 g/s= \dfrac{21000}{5 \times 10^4} = 0.42\text{ g/s}
  4. So the answer is (d) 0.420.42.
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