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MHT CET 2023 (9 May, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2023 (9 May, Shift 2)

Q144MHT CET 2023 · 9 MAY · SHIFT 2Medium

Thermodynamic Processes

A gas is compressed at a constant pressure of 50 N/m250\text{ N/m}^2 from a volume of 10 m310\text{ m}^3 to a volume of 4 m34\text{ m}^3. Energy of 100 J100\text{ J} is then added to the gas by heating. Its internal energy is

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Answer: (a)

  1. Work done by gas W=PΔV=50×(4−10)=−300 JW = P\Delta V = 50 \times (4 - 10) = -300\text{ J} (work is done on the gas).
  2. First law: ΔU=Q−W=100−(−300)=400 J\Delta U = Q - W = 100 - (-300) = 400\text{ J}
  3. So the answer is (a) increased by 400 J400\text{ J}.
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