A gas is contained in closed vessel. The initial temperature of the gas is 100. If the pressure of the gas is increased by 4%, the increase in the temperature of the gas is (a) 2 (b) 3 (c) 4 (d) 5

Answer: (a). Closed vessel: P ∝ T ⇒ (Δ P)/(P) = (Δ T)/(T). T = 100° C = 373 K. Δ T = 0.04 × 373 ≈ 14.9° C This matches none of the options; key gives (a) 2° C.

A gas is contained in closed vessel. The initial temperature of the… | MHT CET 2024 (9 May, Shift 1)

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Gas Laws & Ideal Gas Equation

A gas is contained in closed vessel. The initial temperature of the gas is $100^\circ\text{C}$ . If the pressure of the gas is increased by $4\%$ , the increase in the temperature of the gas is

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Answer: (a)

Closed vessel: $P \propto T \Rightarrow \dfrac{\Delta P}{P} = \dfrac{\Delta T}{T}$ .
$T = 100^\circ$ C $= 373$ K.
$\Delta T = 0.04 \times 373 \approx 14.9^\circ$ C
This matches none of the options; key gives (a) $2^\circ$ C.

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