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JEE Main 2025 (3 Apr, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2025 (3 Apr, Shift 1)

Q87JEE Main 2025 · 3 APR · SHIFT 1Medium

Thermodynamic Processes

A gas is kept in a container having walls which are thermally non-conducting. Initially the gas has a volume of 800 cm3800\text{ cm}^{3} and temperature 27∘C27^\circ\text{C}. The change in temperature when the gas is adiabatically compressed to 200 cm3200\text{ cm}^{3} is:

(Take γ=1.5;γ\gamma = 1.5; \gamma is the ratio of specific heats at constant pressure and at constant volume)

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Answer: (a)

  1. Adiabatic: TVγ−1=TV^{\gamma-1} = constant, so T2=T1(V1V2)γ−1T_2 = T_1\left(\frac{V_1}{V_2}\right)^{\gamma-1}.
  2. T2=300×(4)0.5=600 KT_2 = 300 \times (4)^{0.5} = 600\text{ K}
  3. ΔT=600−300=300 K\Delta T = 600 - 300 = 300\text{ K}
  4. So the answer is (a) 300 K.
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