Student Login

Home›Chapters›Thermodynamics PYQs›Degrees of Freedom & Internal Energy›Question 18

JEE Main 2023 (10 Apr, Shift 2) · Degrees of Freedom & Internal Energy

Degrees of Freedom & Internal Energy question from JEE Main 2023 (10 Apr, Shift 2)

Q18JEE Main 2023 · 10 APR · SHIFT 2Medium

Degrees of Freedom & Internal Energy

A gas mixture consists of 2 moles of oxygen and 4 moles of neon at temperature T. Neglecting all vibrational modes, the total internal energy of the system will be,

Show answer and solution

Answer: (d)

$\text{O}_2$ (no vibration): $f = 5$ ; Ne: $f = 3$ .
$U = 2 \times \frac{5}{2}RT + 4 \times \frac{3}{2}RT = 5RT + 6RT$
So the answer is (d) $11RT$ .

Report a mistake

More questions on Degrees of Freedom & Internal Energy

An insulated container contains a monoatomic gas of molar mass ' m '. The container is…MHT CET 2023 (10 May, Shift 2)
Three vessels of equal capacity have gases at the same temperature and pressure. The…NEET 2022 (Phase 2)
The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will…JEE Main 2022 (28 Jun, Shift 1)
A thermally insulated vessel contains an ideal gas of molecular mass M and ratio of…JEE Main 2022 (26 Jun, Shift 1)
Internal energy of n₁ moles of hydrogen at temperature ' T ' is equal to internal energy…MHT CET 2021 (24 Sep, Shift 1)
Two ideal polyatomic gases at temperatures T1 and T2 are mixed so that there is no loss…JEE Main 2021 (17 Mar, Shift 1)
The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of…JEE Main 2021 (16 Mar, Shift 1)
The internal energy (U), pressure (P) and volume (V) of an ideal gas are related as U =…JEE Main 2021 (26 Feb, Shift 2)