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JEE Main 2020 (2 Sep, Shift 1) · Degrees of Freedom & Internal Energy

Degrees of Freedom & Internal Energy question from JEE Main 2020 (2 Sep, Shift 1)

Q30JEE Main 2020 · 2 SEP · SHIFT 1Medium

Degrees of Freedom & Internal Energy

A gas mixture consists of 3 moles of oxygen and 5 moles of argon at temperature T. Assuming the gases to be ideal and the oxygen bond to be rigid, the total internal energy (in units of RT) of the mixture is:

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Answer: (c)

Rigid $\text{O}_2$ : $f = 5$ ; Ar: $f = 3$ .
$U = 3 \times \frac{5}{2}RT + 5 \times \frac{3}{2}RT = 7.5RT + 7.5RT$
So the answer is (c) 15.

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