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JEE Main 2024 (31 Jan, Shift 2) · Degrees of Freedom & Internal Energy

Degrees of Freedom & Internal Energy question from JEE Main 2024 (31 Jan, Shift 2)

Q11JEE Main 2024 · 31 JAN · SHIFT 2Medium

Degrees of Freedom & Internal Energy

A gas mixture consists of 8 moles of argon and 6 moles of oxygen at temperature T. Neglecting all vibrational modes, the total internal energy of the system is:

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Answer: (b)

Ar: $f = 3$ ; $\text{O}_2$ (no vibration): $f = 5$ .
$U = 8 \times \frac{3}{2}RT + 6 \times \frac{5}{2}RT = 12RT + 15RT$
So the answer is (b) $27RT$ .

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