A gas of certain mass filled in a closed cylinder at a pressure of 3.23 kPa has temperature 50. The gas is now heated to double its temperature. The modified pressure is ______ Pa. Numerical answer type. Work it out, then open the answer.

Answer: 3730. Closed cylinder (constant V): P ∝ T (in kelvin). T₁ = 50° C = 323 K; doubled temperature 100° C = 373 K. P₂ = 3230 × (373)/(323) = 3730 Pa Answer: 3730 Pa

A gas of certain mass filled in a closed cylinder at a pressure of… | JEE Main 2026 (24 Jan, Shift 1)

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Gas Laws & Ideal Gas Equation

A gas of certain mass filled in a closed cylinder at a pressure of 3.23 kPa has temperature $50^\circ\text{C}$ . The gas is now heated to double its temperature. The modified pressure is ______ Pa.

Numerical answer type. Work it out, then open the answer.

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Answer: 3730

Closed cylinder (constant $V$ ): $P \propto T$ (in kelvin).
$T_1 = 50^\circ$ C $= 323$ K; doubled temperature $100^\circ$ C $= 373$ K.
$P_2 = 3230 \times \dfrac{373}{323} = 3730$ Pa
Answer: $3730$ Pa

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