A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio (Cp)/(Cv) of the mixture is (a) 1.62 (b) 1.59 (c) 1.54 (d) 1.4

Answer: (a). Moles: He = 16/4 = 4, O₂ = 16/32 = 0.5. Total CV = 4(1.5R) + 0.5(2.5R) = 7.25R; total CP = 4(2.5R) + 0.5(3.5R) = 11.75R γ = (11.75)/(7.25) ≈ 1.62 So the answer is (a) 1.62.

A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The… | JEE Main 2005 (AIEEE)

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Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation

A gaseous mixture consists of $16\text{ g}$ of helium and $16\text{ g}$ of oxygen. The ratio $\frac{C_p}{C_v}$ of the mixture is

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Answer: (a)

Moles: He $= \dfrac{16}{4} = 4$ , $O_2 = \dfrac{16}{32} = 0.5$ .
Total $C_V = 4(1.5R) + 0.5(2.5R) = 7.25R$ ; total $C_P = 4(2.5R) + 0.5(3.5R) = 11.75R$
$\gamma = \dfrac{11.75}{7.25} \approx 1.62$
So the answer is (a) 1.62.

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Specific Heats of Gases - Cp, Cv, γ & Mayer's Relation question from JEE Main 2005 (AIEEE)

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