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NEET 2012 (AIPMT, Prelims) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from NEET 2012 (AIPMT, Prelims)

Q67NEET 2012 · AIPMT · PRELIMSMedium

Satellites - Orbital Velocity & Period

A geostationary satellite is orbiting the earth at a height of 5R above the surface of the earth, R being the radius of the earth. The time period of another satellite in hours at a height of 2R from the surface of the earth is

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Answer: (c)

Orbit radii: $r_1 = 6R$ ( $T_1 = 24$ h), $r_2 = 3R$ .
$T_2 = 24\left(\frac{3R}{6R}\right)^{3/2} = \frac{24}{2\sqrt{2}}$
$T_2 = 6\sqrt{2}$ h
So the answer is (c).

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