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MHT CET 2025 (25 Apr, Shift 2) · Refraction, Glass Slab & Apparent Depth

Refraction, Glass Slab & Apparent Depth question from MHT CET 2025 (25 Apr, Shift 2)

Q14MHT CET 2025 · 25 APR · SHIFT 2Medium

Refraction, Glass Slab & Apparent Depth

A glass cube of length 21 cm has a small air bubble trapped inside. When viewed normally from the opposite face, its apparent distance is 6 cm. The refractive index of glass and the actual distance of the air bubble from the first surface respectively are

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Answer: (a)

  1. If the bubble is xx from the first surface, its real distance from the opposite face is 21−x21 - x, and apparent distance =21−xμ=6= \dfrac{21 - x}{\mu} = 6.
  2. With one data point, test the options: (a) 21−121.5=6\dfrac{21 - 12}{1.5} = 6 cm ✓.
  3. Others fail: (b) 7/1.55≈4.57/1.55 \approx 4.5, (c) 10/1.6=6.2510/1.6 = 6.25, (d) 12/1.5=812/1.5 = 8.
  4. So the answer is (a) 1.51.5, 1212 cm.
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