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MHT CET 2024 (16 May, Shift 1) · Refraction, Glass Slab & Apparent Depth

Refraction, Glass Slab & Apparent Depth question from MHT CET 2024 (16 May, Shift 1)

Q19MHT CET 2024 · 16 MAY · SHIFT 1Easy

Refraction, Glass Slab & Apparent Depth

A glass slab of thickness 4.8 cm is placed on the piece of paper on which an ink dot is marked. By how much distance would an ink dot appear to be raised? (The refractive index of glass $= 1.5$ )

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Answer: (a)

Normal shift $= t\left(1 - \frac{1}{\mu}\right)$
$= 4.8\left(1 - \frac{1}{1.5}\right) = 4.8 \times \frac{1}{3} = 1.6\text{ cm}$
So the answer is (a) 1.6 cm.

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