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MHT CET 2026 (19 Apr, Shift 1) · Refraction, Glass Slab & Apparent Depth

Refraction, Glass Slab & Apparent Depth question from MHT CET 2026 (19 Apr, Shift 1)

Q4MHT CET 2026 · 19 APR · SHIFT 1Easy

Refraction, Glass Slab & Apparent Depth

A glass slab of thickness $6.0$ cm is placed on the piece of paper on which an inkdot is marked. By how much distance would an inkdot appear to be raised? The velocity of light in glass is $2 \times 10^{8}$ ms $-1$ and that in air is $3 \times 10^{8}$ ms $-1$ .

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Answer: (a)

$\mu = \frac{c}{v} = \frac{3 \times 10^8}{2 \times 10^8} = 1.5$
Normal shift $= t\left(1 - \frac{1}{\mu}\right) = 6\left(1 - \frac{2}{3}\right)$
$= 2.0\text{ cm}$ . So the answer is (a).

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