A group of lamps having total power rating of 1000 W is supplied by an AC voltage of E = 200 sin (310t + 60°), the rms value of current flowing through the circuit is (a) 10 A (b) 5√(2) A (c) 20 A (d) 10√(2) A

Answer: (b). Erms = (200)/(√(2)) = 100√(2) V For lamps (resistive), P = Erms Irms. Irms = (1000)/(100√(2)) = (10)/(√(2)) = 5√(2) A So the answer is (b) 5√(2) A.

A group of lamps having total power rating of 1000 W is supplied by… | MHT CET 2023 (13 May, Shift 2)

Q20MHT CET 2023 · 13 MAY · SHIFT 2Easy

AC Basics: Peak, RMS & Average Values

A group of lamps having total power rating of $1000\text{ W}$ is supplied by an AC voltage of $E = 200 \sin(310t + 60^\circ)$ , the rms value of current flowing through the circuit is

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Answer: (b)

$E_{rms} = \frac{200}{\sqrt{2}} = 100\sqrt{2}$ V
For lamps (resistive), $P = E_{rms} I_{rms}$ .
$I_{rms} = \frac{1000}{100\sqrt{2}} = \frac{10}{\sqrt{2}} = 5\sqrt{2}$ A
So the answer is (b) $5\sqrt{2}$ A.

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AC Basics: Peak, RMS & Average Values question from MHT CET 2023 (13 May, Shift 2)

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