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JEE Main 2026 (4 Apr, Shift 2) · Time of Flight, Maximum Height & Range

Time of Flight, Maximum Height & Range question from JEE Main 2026 (4 Apr, Shift 2)

Q3JEE Main 2026 · 4 APR · SHIFT 2Easy

Time of Flight, Maximum Height & Range

A gun mounted on the ground fires bullets in all directions with same speed. The farthest distance the bullets could reach is 6.4 m. The speed of the bullets from the gun is ‾ m/s\underline{\qquad}\text{ m/s}. (take g=10 m/s2g = 10\text{ m/s}^{2})

Numerical answer type. Work it out, then open the answer.

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Answer: 8

  1. Farthest reach on level ground is the maximum range: Rmax=u2gR_{max} = \frac{u^2}{g}
  2. u2=6.4×10=64u^2 = 6.4 \times 10 = 64
  3. u=8 m/su = 8\text{ m/s}
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