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JEE Main 2018 (16 Apr, Shift 1) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from JEE Main 2018 (16 Apr, Shift 1)

Q52JEE Main 2018 · 16 APR · SHIFT 1Medium

Ohm's Law, Resistivity & Temperature

A heating element has a resistance of 100 Ω\Omega at room temperature. When it is connected to a supply of 220 V, a steady current of 2 A passes in it and temperature is 500oC more than room temperature. What is the temperature coefficient of resistance of the heating element?

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Answer: (d)

  1. Hot resistance R=220/2=110 ΩR = 220/2 = 110\ \Omega.
  2. 110=100(1+500α)⇒α=0.1500=2×10−4 ∘C−1110 = 100(1 + 500\alpha) \Rightarrow \alpha = \dfrac{0.1}{500} = 2\times10^{-4}\ ^\circ\text{C}^{-1}
  3. The answer is (d).
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