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JEE Main 2024 (5 Apr, Shift 2) · Friction Basics

Friction Basics question from JEE Main 2024 (5 Apr, Shift 2)

Q3JEE Main 2024 · 5 APR · SHIFT 2Easy

Friction Basics

A heavy box of mass $50\text{ kg}$ is moving on a horizontal surface. If co-efficient of kinetic friction between the box and horizontal surface is 0.3 then force of kinetic friction is:

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Answer: (b)

$f_k = \mu_k N = \mu_k mg$
$f_k = 0.3 \times 50 \times 9.8 = 147$ N
So the answer is (b) 147 N.

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