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JEE Main 2024 (27 Jan, Shift 2) · Torque, Couple & Equilibrium of Rigid Bodies

Torque, Couple & Equilibrium of Rigid Bodies question from JEE Main 2024 (27 Jan, Shift 2)

Q14JEE Main 2024 · 27 JAN · SHIFT 2Medium

Torque, Couple & Equilibrium of Rigid Bodies

A heavy iron bar of weight 12 kg12\text{ kg} is having its one end on the ground and the other on the shoulder of a man. The rod makes an angle 60∘60^\circ with the horizontal, the weight experienced by the man is:

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Answer: (a)

  1. In the key's working the shoulder's reaction NN is perpendicular to the bar (smooth contact). Moments about the end on the ground.
  2. N×L=W×L2cos⁡60∘N \times L = W \times \frac{L}{2}\cos 60^\circ
  3. N=W2cos⁡60∘=122×12=3N = \frac{W}{2}\cos 60^\circ = \frac{12}{2} \times \frac{1}{2} = 3 kg wt
  4. So the answer is (a) 3 kg.
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