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NEET 1991 (AIPMT) · Two-Body Friction

Two-Body Friction question from NEET 1991 (AIPMT)

Q13NEET 1991 · AIPMTEasy

Two-Body Friction

A heavy uniform chain lies on horizontal table top. If the coefficient of friction between the chain and the table surface is 0.25, then the maximum fraction of the length of the chain that can hang over one edge of the table is

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Answer: (a)

Let a fraction $f$ hang. Weight of hanging part $= f\,Mg$ ; maximum friction on the table part $= \mu(1-f)Mg$ .
Limiting case: $f = \mu(1-f) \Rightarrow f = \frac{\mu}{1+\mu}$
$f = \frac{0.25}{1.25} = 0.2$
So the answer is (a) 20%.

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