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JEE Main 2016 (10 Apr, Shift 1) · Combination of Lenses

Combination of Lenses question from JEE Main 2016 (10 Apr, Shift 1)

Q69JEE Main 2016 · 10 APR · SHIFT 1Difficult

Combination of Lenses

A hemispherical glass body of radius 10 cm and refractive index 1.5 is silvered on its curved surface. A small air bubble is 6 cm below the flat surface inside it along the axis. The position of the image of the air bubble made by the mirror is seen:

Figure

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Answer: (c)

  1. Curved surface is a concave mirror: R=10R = 10, f=5 cmf = 5\text{ cm}; bubble is 10−6=4 cm10 - 6 = 4\text{ cm} from the pole.
  2. 1v=−15+14=120⇒v=20 cm\frac{1}{v} = -\frac{1}{5} + \frac{1}{4} = \frac{1}{20} \Rightarrow v = 20\text{ cm} behind the pole, i.e. 30 cm30\text{ cm} below the flat surface.
  3. Seen through the flat surface: apparent depth =301.5=20 cm= \frac{30}{1.5} = 20\text{ cm}
  4. So the answer is (c) 20 cm below flat surface.
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