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JEE Main 2023 (24 Jan, Shift 1) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from JEE Main 2023 (24 Jan, Shift 1)

Q40JEE Main 2023 · 24 JAN · SHIFT 1Medium

Thermometry & Thermal Expansion

A hole is drilled in a metal sheet. At 27∘C27^\circ\text{C}, the diameter of hole is 5 cm. When the sheet is heated to 177∘C177^\circ\text{C}, the change in the diameter of hole is d×10−3\text{d} \times 10^{-3} cm. The value of d will be __________ if coefficient of linear expansion of the metal is 1.6×10−5/∘1.6 \times 10^{-5}/^\circC.

Numerical answer type. Work it out, then open the answer.

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Answer: 12

  1. A hole expands like the material around it: Δd=dαΔT\Delta d = d\alpha\Delta T.
  2. Δd=5×1.6×10−5×150=0.012\Delta d = 5 \times 1.6\times10^{-5} \times 150 = 0.012 cm
  3. 0.012=12×10−30.012 = 12\times10^{-3} cm, so d=12d = 12.
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