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MHT CET 2021 (20 Sep, Shift 2) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from MHT CET 2021 (20 Sep, Shift 2)

Q87MHT CET 2021 · 20 SEP · SHIFT 2Medium

Electric Potential & Equipotentials

A hollow charged metal sphere has radius 'R'. If the potential difference between its surface and a point at a distance '5 R' from the centre is $V$ , then magnitude of electric field Intensity at a distance '5R' from the centre of sphere is

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Answer: (b)

$V = kQ\left(\frac{1}{R} - \frac{1}{5R}\right) = \frac{4kQ}{5R} \Rightarrow kQ = \frac{5VR}{4}$
$E(5R) = \frac{kQ}{25R^2} = \frac{5VR}{100R^2} = \frac{V}{20R}$
So the answer is (b) $\frac{V}{20R}$ .

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