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MHT CET 2025 (20 Apr, Shift 1) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from MHT CET 2025 (20 Apr, Shift 1)

Q22MHT CET 2025 · 20 APR · SHIFT 1Easy

Electric Flux & Gauss's Law

A hollow cylinder has a charge of ' qq ' CC within it. If ϕ\phi is the electric flux associated with the curved surface B, the flux linked with the plane surface A will be

Figure

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Answer: (d)

  1. Total flux: ϕA+ϕB+ϕC=qε0\phi_A + \phi_B + \phi_C = \dfrac{q}{\varepsilon_0}, with ϕB=ϕ\phi_B = \phi (curved surface).
  2. By symmetry the flat ends share equally: ϕA=ϕC\phi_A = \phi_C.
  3. ϕA=12(qε0−ϕ)\phi_A = \dfrac{1}{2}\left(\dfrac{q}{\varepsilon_0} - \phi\right)
  4. So the answer is (d).
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