Physics Circle home Student Login

Home›Chapters›Electrostatics PYQs›Electric Flux & Gauss's Law›Question 37

MHT CET 2024 (16 May, Shift 2) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from MHT CET 2024 (16 May, Shift 2)

Q37MHT CET 2024 · 16 MAY · SHIFT 2Easy

Electric Flux & Gauss's Law

A hollow cylinder has charge ' qq ' CC within it. If ' ϕ\phi ' is the electric flux associated with the curved surface B, the flux linked with the plane surface A will be:

Figure

Show answer and solution

Answer: (a)

  1. Total flux: ϕA+ϕB+ϕC=qε0\phi_A + \phi_B + \phi_C = \dfrac{q}{\varepsilon_0}, with ϕB=ϕ\phi_B = \phi (curved surface).
  2. By symmetry the flat ends share equally: ϕA=ϕC\phi_A = \phi_C.
  3. ϕA=12(qε0−ϕ)\phi_A = \dfrac{1}{2}\left(\dfrac{q}{\varepsilon_0} - \phi\right)
  4. So the answer is (a).
Report a mistake

More questions on Electric Flux & Gauss's Law