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MHT CET 2021 (21 Sep, Shift 2) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from MHT CET 2021 (21 Sep, Shift 2)

Q86MHT CET 2021 · 21 SEP · SHIFT 2Medium

Electric Potential & Equipotentials

A hollow metal sphere has a radius 'r'. The potential difference between a point on its surface and at a point at a distance '3r' from its centre is 'V'. The electric intensity at the distance '3r' from the centre of the sphere will be:

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Answer: (d)

$V = kQ\left(\frac{1}{r} - \frac{1}{3r}\right) = \frac{2kQ}{3r} \Rightarrow kQ = \frac{3Vr}{2}$
$E(3r) = \frac{kQ}{9r^2} = \frac{V}{6r}$
So the answer is (d) $\frac{V}{6r}$ .

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