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JEE Main 2024 (5 Apr, Shift 2) · Rolling Motion

Rolling Motion question from JEE Main 2024 (5 Apr, Shift 2)

Q23JEE Main 2024 · 5 APR · SHIFT 2Easy

Rolling Motion

A hollow sphere is rolling on a plane surface about its axis of symmetry. The ratio of rotational kinetic energy to its total kinetic energy is $\frac{x}{5}$ . The value of $x$ is _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 2

Hollow sphere: $\frac{k^2}{R^2} = \frac{2}{3}$ .
$\frac{K_{rot}}{K_{total}} = \frac{2/3}{1 + 2/3} = \frac{2}{5}$
So $x = 2$ .

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