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JEE Main 2019 (10 Jan, Shift 1) · Rolling Motion

Rolling Motion question from JEE Main 2019 (10 Jan, Shift 1)

Q72JEE Main 2019 · 10 JAN · SHIFT 1Medium

Rolling Motion

A homogeneous solid cylindrical roller of radius R and mass M is pulled on a cricket pitch by a horizontal force. Assuming rolling without slipping, angular acceleration of the cylinder is -

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Answer: (b)

  1. Force FF at the axle, friction ff backward: F−f=MaF - f = Ma, fR=12MR2αfR = \frac{1}{2}MR^2\alpha with a=Rαa = R\alpha.
  2. f=12Ma⇒F=32Ma⇒a=2F3Mf = \frac{1}{2}Ma \Rightarrow F = \frac{3}{2}Ma \Rightarrow a = \dfrac{2F}{3M}.
  3. α=aR=2F3MR\alpha = \dfrac{a}{R} = \dfrac{2F}{3MR}.
  4. So the answer is (b) (options write mm for MM).
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