A horizontal pipe carries water in a streamline flow. At point along the pipe, where the cross- sectional area is A₁, the velocity of water is V₁ and the pressure is P₁. What is the pressure of water at another point where the cross-sectional area is A₂? (a) P₁ - (ρ V₂²)/(2A₁²)(A₂² - A₁²) (b) P₁ + (ρ V₁²)/(2A₂²)(A₂² - A₁²) (c) P₁ ρ V₁² (A₁² - A₂²) (d) P/ρ V₁² A₂²

Answer: (b). Continuity: V₂ = (A₁ V₁)/(A₂) Bernoulli (horizontal): P₂ = P₁ + 1/2ρ (V₁² - V₂²) = P₁ + 1/2ρ V₁²(1 - (A₁²)/(A₂²)) P₂ = P₁ + (ρ V₁²)/(2A₂²)(A₂² - A₁²) So the answer is (b).

A horizontal pipe carries water in a streamline flow. At point along… | MHT CET 2026 (16 Apr, Shift 2)

Q2MHT CET 2026 · 16 APR · SHIFT 2Medium

Bernoulli's Equation

A horizontal pipe carries water in a streamline flow. At point along the pipe, where the cross- sectional area is $A_1$ , the velocity of water is $V_1$ and the pressure is $P_1$ . What is the pressure of water at another point where the cross-sectional area is $A_2$ ?

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Answer: (b)

Continuity: $V_2 = \dfrac{A_1 V_1}{A_2}$
Bernoulli (horizontal): $P_2 = P_1 + \frac{1}{2}\rho (V_1^2 - V_2^2) = P_1 + \frac{1}{2}\rho V_1^2\left(1 - \dfrac{A_1^2}{A_2^2}\right)$
$P_2 = P_1 + \dfrac{\rho V_1^2}{2A_2^2}(A_2^2 - A_1^2)$
So the answer is (b).

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Bernoulli's Equation question from MHT CET 2026 (16 Apr, Shift 2)

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