A horizontal ray of light is incident on the right angled prism with prism angle 6°. If the refractive index of the material of the prism is 1.5, then the angle of emergence will be: (a) 9° (b) 10° (c) 4° (d) 6°

Answer: (a). The horizontal ray hits the vertical face normally, so it goes straight in: r₁ = 0. r₁ + r₂ = A ⇒ r₂ = 6° at the slanted face. sin e = μ sin r₂ ≈ 1.5 × 6° (small angles) e ≈ 9° So the answer is (a) 9°.

A horizontal ray of light is incident on the right angled prism with… | NEET 2023

Q39NEET 2023Easy

Prism, Dispersion & Scattering

A horizontal ray of light is incident on the right angled prism with prism angle $6^\circ$ . If the refractive index of the material of the prism is 1.5, then the angle of emergence will be:

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Answer: (a)

The horizontal ray hits the vertical face normally, so it goes straight in: $r_1 = 0$ .
$r_1 + r_2 = A \Rightarrow r_2 = 6^\circ$ at the slanted face.
$\sin e = \mu \sin r_2 \approx 1.5 \times 6^\circ$ (small angles)
$e \approx 9^\circ$
So the answer is (a) $9^\circ$ .

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