Spring Systems question from MHT CET 2026 (15 May, Shift 2)

Answer: (b)

1. At the mean position momentum is conserved: $mv = 2mv' \Rightarrow v' = v/2$.
2. $\omega' = \sqrt{\frac{k}{2m}} = \frac{\omega}{\sqrt{2}}$
3. $A_2 = \frac{v'}{\omega'} = \frac{v/2}{\omega/\sqrt{2}} = \frac{A_1}{\sqrt{2}}$
4. $\frac{A_1}{A_2} = \sqrt{2}$, so the answer is (b).