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JEE Main 2022 (30 Jun, Shift 1) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from JEE Main 2022 (30 Jun, Shift 1)

Q42JEE Main 2022 · 30 JUN · SHIFT 1Medium

Transitions, Photon Emission & Excitation

A hydrogen atom in its first excited state absorbs a photon of energy x ×\times 10−-2 eV and excited to a higher energy state where the potential energy of electron is−1{}^{-1}.08 eV. The value of x is ______________.

Numerical answer type. Work it out, then open the answer.

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Answer: 286

  1. Total energy =12×= \frac{1}{2} \times PE =−1.082=−0.54= \frac{-1.08}{2} = -0.54 eV (this is n=5n = 5).
  2. First excited state energy =−3.4= -3.4 eV.
  3. Absorbed energy =−0.54−(−3.4)=2.86= -0.54 - (-3.4) = 2.86 eV =286×10−2= 286 \times 10^{-2} eV
  4. So x=286x = 286.
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