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JEE Main 2022 (27 Jun, Shift 1) · Bohr Model: Orbits, Speed & Angular Momentum

Bohr Model: Orbits, Speed & Angular Momentum question from JEE Main 2022 (27 Jun, Shift 1)

Q83JEE Main 2022 · 27 JUN · SHIFT 1Medium

Bohr Model: Orbits, Speed & Angular Momentum

A hydrogen atom in its ground state absorbs 10.2 eV of energy. The angular momentum of electron of the hydrogen atom will increase by the value of:

(Given, Planck's constant = 6.6 ×\times 10−-34 Js).

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Answer: (b)

  1. E1=−13.6 eVE_1 = -13.6\text{ eV}, E2=−3.4 eVE_2 = -3.4\text{ eV}, so 10.2 eV10.2\text{ eV} takes the electron from n=1n=1 to n=2n=2.
  2. Bohr: L=nh2πL = \frac{nh}{2\pi}, so ΔL=h2π\Delta L = \frac{h}{2\pi}
  3. ΔL=6.6×10−342×3.14≈1.05×10−34 Js\Delta L = \frac{6.6\times10^{-34}}{2\times3.14} \approx 1.05\times10^{-34}\text{ Js}
  4. So the answer is (b) 1.05×10−34 Js1.05\times10^{-34}\text{ Js}.
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