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MHT CET 2026 (19 May, Shift 1) · Motion Under Gravity

Motion Under Gravity question from MHT CET 2026 (19 May, Shift 1)

Q6MHT CET 2026 · 19 MAY · SHIFT 1Medium

Motion Under Gravity

A juggler throws balls into air. He throws one ball whenever the previous one is at its highest point. If he throws 4 balls in one second, the height from which each ball returns is nearly [acceleration due to gravity is 9.89.8 m/s2{}^{2}]

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Answer: (a)

  1. 4 balls per second: interval =0.25= 0.25 s, which equals the time to reach the top.
  2. H=12gt2=12×9.8×0.252≈0.306H = \frac{1}{2}gt^2 = \frac{1}{2} \times 9.8 \times 0.25^2 \approx 0.306 m
  3. H≈30H \approx 30 cm. So the answer is (a) 30 cm.
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