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JEE Main 2022 (29 Jul, Shift 2) · Motion Under Gravity

Motion Under Gravity question from JEE Main 2022 (29 Jul, Shift 2)

Q24JEE Main 2022 · 29 JUL · SHIFT 2Medium

Motion Under Gravity

A juggler throws balls vertically upwards with same initial velocity in air. When the first ball reaches its highest position, he throws the next ball. Assuming the juggler throws n balls per second, the maximum height the balls can reach is

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Answer: (d)

$n$ balls per second: interval $= \frac{1}{n}$ s, which equals the time to reach the top.
$H = \frac{1}{2}gt^2 = \frac{1}{2}g\left(\frac{1}{n}\right)^2$
So the answer is (d) $\frac{g}{2n^2}$ .

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