A kathak dancer is standing on horizontal surface with folded hands… | MHT CET 2026 (18 Apr, Shift 2)

Q10MHT CET 2026 · 18 APR · SHIFT 2Medium

Angular Momentum & its Conservation

A kathak dancer is standing on horizontal surface with folded hands. In the begining dancer is rotating about his central axis and his kinetic energy is 'K' at that time. The kathak dancer now stretches his arms so that the moment of inertia of the dancer becomes three times and the angular velocity becomes one-third. The kinetic energy of the dancer now is

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Answer: (b)

$K=\frac12I\omega^2$
$K'=\frac12(3I)\left(\frac{\omega}{3}\right)^2=\frac13\cdot\frac12I\omega^2$
$K'=\frac{K}{3}$
So the answer is (b) $\frac{K}{3}$ .

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Angular Momentum & its Conservation question from MHT CET 2026 (18 Apr, Shift 2)

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